limx→af(x)=0 and limx→ag(x)=0limit over x right arrow a of f of x equals 0 and limit over x right arrow a of g of x equals 0
limx→af(x)g(x)=limx→af′(x)g′(x)limit over x right arrow a of f of x over g of x end-fraction equals limit over x right arrow a of f prime of x over g prime of x end-fraction provided the limit on the right exists (or is ±∞plus or minus infinity Step-by-Step Application 4.7 / 10 ActionThri...
L'Hôpital's Rule allows you to resolve indeterminate limits by differentiating the numerator and the denominator separately. Suppose that are differentiable and on an open interval that contains (except possibly at limx→af(x)=0 and limx→ag(x)=0limit over x right arrow a
∞∞the fraction with numerator infinity and denominator infinity end-fraction Feature Overview: L'Hôpital's Rule 4.7 / 10 ActionThri...